2x^(2/3)+7x^(1/3)-15=0

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Solution for 2x^(2/3)+7x^(1/3)-15=0 equation: 


x in (-oo:+oo)

2*x^(2/3)+7*x^(1/3)-15 = 0

t_1 = x^(1/3)

2*t_1^2+7*t_1^1-15 = 0

2*t_1^2+7*t_1-15 = 0

DELTA = 7^2-(-15*2*4)

DELTA = 169

DELTA > 0

t_1 = (169^(1/2)-7)/(2*2) or t_1 = (-169^(1/2)-7)/(2*2)

t_1 = 3/2 or t_1 = -5

t_1 = -5

x^(1/3)+5 = 0

1*x^(1/3) = -5 // : 1

x^(1/3) = -5

( -5 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 3/2

x^(1/3)-3/2 = 0

1*x^(1/3) = 3/2 // : 1

x^(1/3) = 3/2

x^(1/3) = 3/2 // ^ 3

x = 27/8

x = 27/8

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